AscW() function

[Natter]

Hi, all !

VBA (Excel) has an AscW() function. It is used to obtain the Unicode character code. How do I do this on FW ?

[nageswaragunupudi]

Please try

Code: Select all

HB_UTF8CHR( nChar )
 

Maybe that is what you are looking for.

[AntoninoP]

AscW return the unicode value from character or string. I think the Harbour version is HB_UTF8ASC:

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HB_UTF8ASC( <cUtf8> ) -> <nUnicode>

HB_UTF8CHR is:

Code: Select all

HB_UTF8CHR( <nUniVal> ) -> <cUtf8Char>

[nageswaragunupudi]

Yes, Mr. Antonio
And thanks for the correction.

[Natter]

Yes, the HB_UTF8Asc() function suits me, but it is not available for FWH18.06

[nageswaragunupudi]

This is not FWH function.
This is a Harbour function available both in Harbour and xHarbour.

[Natter]

I downloaded xHarbour Binaries 1.2.3 Rev. 10252 for BCC 5.8.2 with xharbour.org But when linking the hb_utf8asc function is not detected

[Enrico Maria Giordano]

I confirm: there is no hb_utf8asc() function in xHarbour. I can try to add it to xHarbour, if you really need it.

EMG

[Natter]

Yes, I do. I will be very grateful to you

[Enrico Maria Giordano]

Ok, I'll see what I can do...

EMG

[Enrico Maria Giordano]

Please, try this function and let me know if there are any problems:

Code: Select all

#include "Fivewin.ch"


FUNCTION MAIN()

    ? HB_UTF8ASC( "A" )

    RETURN NIL


#pragma BEGINDUMP


#include "error.ch"
#include "hbapierr.h"


static BOOL utf8tou16nextchar( UCHAR ucChar, int * n, USHORT * uc )
{
   if( *n > 0 )
   {
      if( ( ucChar & 0xc0 ) != 0x80 )
         return FALSE;
      *uc = ( *uc << 6 ) | ( ucChar & 0x3f );
      ( *n )--;
      return TRUE;
   }

   *n    = 0;
   *uc   = ucChar;
   if( ucChar >= 0xc0 )
   {
      if( ucChar < 0xe0 )
      {
         *uc   &= 0x1f;
         *n    = 1;
      }
      else if( ucChar < 0xf0 )
      {
         *uc   &= 0x0f;
         *n    = 2;
      }
      else if( ucChar < 0xf8 )
      {
         *uc   &= 0x07;
         *n    = 3;
      }
      else if( ucChar < 0xfc )
      {
         *uc   &= 0x03;
         *n    = 4;
      }
      else if( ucChar < 0xfe )
      {
         *uc   &= 0x01;
         *n    = 5;
      }
   }
   return TRUE;
}


HB_FUNC( HB_UTF8ASC )

{

   const char * pszString = hb_parc( 1 );



   if( pszString )

   {

      HB_SIZE nLen = hb_parclen( 1 );

      USHORT wc = 0;

      int n = 0;



      while( nLen )

      {

         if( ! utf8tou16nextchar( ( unsigned char ) *pszString, &n, &wc ) )

            break;

         if( n == 0 )

            break;

         pszString++;

         nLen--;

      }

      hb_retnint( wc );

   }

   else

      hb_errRT_BASE_SubstR( EG_ARG, 3012, NULL, HB_ERR_FUNCNAME, HB_ERR_ARGS_BASEPARAMS );

}

#pragma ENDDUMP

EMG

[Natter]

Latin's fine. However, this function returns incorrect Unicode Cyrillic characters

[Enrico Maria Giordano]

Can you send me a sample showing the problem, please?

EMG

[nageswaragunupudi]

Working correctly for me with this test:

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   local n, c

   n  := 0xE100
   c  := HB_UTF8CHR( n )

   ? HB_UTF8ASC( HB_UTF8CHR( n ) ) == n  // --> .T.
   ? HB_UTF8CHR( HB_UTF8ASC( c ) ) == c  //  --> .T.
 

[Natter]

I didn't understand. There is a character with a code of 128 (1 byte) If you convert this character to Unicode it will consist of 2 bytes and its code will be 1040. How can I do this through the HB_UTF8ASC function() ?