Executing one copy of an external application

Dan Landon · Post by **Dan Landon** » Sat Mar 25, 2006 1:59 pm

I am trying to execute calc.exe and I only want one copy to be running at a time. I am using WinExec("calc") to execute the program, but I don't want multiple copies. If calc.exe is already running I want to show the running copy and not start a new copy.

Does anyone know the procedure for checking if a copy is running and if so then show it rather than executing another copy?

Dan

Post by **Antonio Linares** » Sat Mar 25, 2006 6:25 pm

Dan,

You may use FindWindow() to first locate the app. Please review this thread:
http://fivetechsoft.com/forums/viewtopi ... dwindow%2A

Dan Landon · Post by **Dan Landon** » Sun Mar 26, 2006 1:13 am

I got the code working that finds the window, but I can't seem to get the calc application to come to the foreground. ShowWindow(hWnd) doesn't seem to do it.

Dan

Sun Mar 26, 2006 8:02 am

Try SetForegroundWindow() or BringWindowToTop().

EMG

Post by **Antonio Linares** » Sun Mar 26, 2006 8:02 am

Dan,

Please do a MsgInfo( GetWindowText( hWnd ) ) just to be sure it is the calc, before doing ShowWindow( hWnd ).

Dan Landon · Post by **Dan Landon** » Sun Mar 26, 2006 11:52 am

BringWindowToTop() worked.

Thanks
Dan